What is the required input pressure to achieve a force of 200 lbs in a piston with a blank side of 10 sq. inches?

What is the required input pressure to achieve a force of 200 lbs in a piston with a blank side of 10 sq. inches?

• A. 10 psi
• B. 15 psi
• C. 20 psi
• D. 25 psi

Answer: (C)

To determine the required input pressure to achieve a force of 200 pounds using a piston with a blank side area of 10 square inches, you can use the formula that relates pressure, force, and area: Pressure (P) = Force (F) / Area (A). In this case, you're looking to find the pressure that would create a force of 200 lbs when applied over an area of 10 sq. inches. By rearranging the formula, you would calculate it as follows: P = 200 lbs / 10 sq. inches = 20 psi. Thus, the required input pressure to achieve a force of 200 lbs in this scenario is indeed 20 psi, making this the correct answer. This reflects the fundamental principles of hydraulics, where pressure is needed to exert a force over a specific area.

To determine the required input pressure to achieve a force of 200 pounds using a piston with a blank side area of 10 square inches, you can use the formula that relates pressure, force, and area:

Pressure (P) = Force (F) / Area (A).

In this case, you're looking to find the pressure that would create a force of 200 lbs when applied over an area of 10 sq. inches.

By rearranging the formula, you would calculate it as follows:

P = 200 lbs / 10 sq. inches = 20 psi.

Thus, the required input pressure to achieve a force of 200 lbs in this scenario is indeed 20 psi, making this the correct answer. This reflects the fundamental principles of hydraulics, where pressure is needed to exert a force over a specific area.